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        ?

        On Existence of Local Solu tions of a M ovingBoundary Prob lem M odelling Chem otaxis in 1-D

        2014-05-13 02:38:36WUShaohuaandYUEBo

        WU Shaohua and YUEBo

        SchoolofM athematicsand Statistics,Wuhan University,Wuhan 430072,China.

        On Existence of Local Solu tions of a M oving
        Boundary Prob lem M odelling Chem otaxis in 1-D

        WU Shaohua and YUEBo?

        SchoolofM athematicsand Statistics,Wuhan University,Wuhan 430072,China.

        Received 23Ap ril2014;Accep ted 31August2014

        .w e p rove the local existence and uniqueness of am oving boundary p roblem m odeling chem otactic phenom ena.We also get the exp licit rep resentative for the m oving boundary in a special case.

        Keller-Segelm odelof chem otaxis;m oving boundary;localexistence;special case.

        1 In troduction

        In thispaper,w eare in terested in am oving boundary p roblem due to a chem otaxism odel w hich w as introduced by Keller and Segel[1].Them odel readsas follow s

        w here u(x,t)and v(x,t)stand respectively for the density of the considered species and that of the chem ical w hich triggers them ovem ent,constantsχ,γ,μandβare positive param eters,?is a bounded open subset in RN(N≥1)w ith sm ooth boundary??,and n is unit ou ter norm al vector of??.The p roblem(1.1)is intensively stud ied by m any

        au thors and m ost resu lts have been devoted to the investigation of som e lim it cases correspond ing to particu lar choicesof the param etersχ,γ,μandβabove.Oneof them is that the d iffusive velocity ofγtends to infinity,w hich leads to the follow ing system(see[2])

        w here R

        ?u0d x=|?|,|?|rep resents the volum e of?.

        For the p roblem(1.2),m any resu lts have been gained by som e authors(see for instance[2–6]).Since the spatial d iffusive velocity of v ism uch faster than that of u,it m akes sense that the spatial dom ain occupied by u is a subsetof the spatial dom ain occup ied by v at the sam e tim e.In otherw ords,let??RNbe a bounded open dom ain and?0???be an open sub-dom ain.Assum e a popu lation density u(x,0)occupying the dom ain?0,and in the ou tside of?0the popu lation density u(x,0)≡0 and the external signal v occupying?.For t>0,u(x,t)sp reads to dom ain?t??,let??tdenote the boundary of?tand ntdenote the ou ter norm al vector of??t,thenΓt=??t×(0,T)is the m oving boundary.

        The spatial d iffusion of species is referred to them oving boundary of?tw hich is occup ied by the specie at the tim e t≥0.Observe the flux is increasing w ith respect to the density of the species,so itw ou ld be reasonable to suppose that flux is p roportional to the density.Thusw e have follow ing flux cond ition on??t,

        w here k(x,t)is a positive function,and 1/k(x,t)>0 ism ass flow ratio. On the other hand,noticing that the fu ll flux on??tis

        By conservation of popu lation,one has

        w here vntis the norm ald iffusion velocity of??t. Assum eΓt:Φ(x,t)=0,then

        Notice that

        thus(1.6)and(1.7)give

        We use(1.8)in(1.5)to obtain

        A t lastw e obtain the cond itionsof them oving boundaryΓt

        Therefore the fu llm oving boundary p roblem reads

        w hereΓt:Φ(x,t)=0 is them oving boundary.

        Rem ark 1.1.If N=1 andΓt:x-h(t)=0,then?Φ=1 and?Φ/?t=-d h/d t,the cond itions of them oving boundary convert into

        Rem ark 1.2.Under the case of Rem ark 1.1,if u>0 onΓt,then(1.14)isequivalen t to

        We consider one d im ensionalm oving boundary p roblem(1.12).W ithou t loss of generality,w e assum e that?0=(0,b)w ith 0<b<1,?=(0,1),and for sim p licity,letχ=1.In this case,them oving boundary p roblem can be regarded as follow ing p roblem

        w here u0>0 and R?0u0d x=1.H.Chen and S.Wu(see[7])have given the localexistence and uniquenessof thism oving boundary p roblem(1.16)for the case k(x,t)≡k,w here k>0 isa constant,gotten theexp licit rep resentative for them oving boundary,and show ed the finite-tim e blow up and chem otactic collapse for the solu tion of the p roblem.

        In this paperw ew ou ld d iscuss the case of k(x,t)∈C([0,1]×[0,T0]),t0<T0,w here T0is a given positive constan t.

        2 M ain resu lts

        Letus consider the follow ing system:

        w here k(x,t)∈C([0,1]×[0,T0]),u0>0 and R?0u0d x=1.Ou r app roach here is to find a rad ically symm etric solu tion for the p roblem(2.1)We need to find a pair(u,v)and a cu rveΓt:x=h(t),h(0)=b,to solve them oving boundary p roblem(2.1).

        Now,for tw o positive constants M0andσ,satisfying M0<m in{b,1-b}/(2t0),t0<T0and 1<σ<2,w e define

        which are thesolutionsof(2.1)forsome t0>0 smallenough.

        3 Som e lemm as

        and for each 1<σ<2 and t0smallenough

        where C dependson M0but is independent oft0and h∈Bt0.

        Proof.Take the transform

        w here 0<ξ<1,0<τ<t0.

        so the p roblem(3.7)has a unique solu tion

        for each t0.

        Thus

        We know that Tt1(τ)isa holom orphic sem igroup on X and

        Thus for f∈Hλ,one has

        w here C is dependenton M0but independentof t1.

        If t′>0,then take t1=t′in(3.8),one has

        In particu larw e have

        By using the estim ate(3.9),one can deduce

        w here C dependson M0bu t is independen tof t′and h∈Bt0.

        Accord ing to(3.10)and(3.13)-(3.15),for t′sm allenough,it is obvious that

        In case of t′=0,then for each 0≤t2≤t0,w e have

        From(3.16)and(3.17)w e can easily obtain the estim ate(3.4),Lemm a 3.1 is p roved.

        For the p roblem(3.2),ifωsatisfies that R10ω(ξ,t)dξ=1 for each t,then from a d irect calcu lation,one has

        So w e know

        4 Localexistenceand uniqueness form oving boundary p rob lem

        In thissection,w e p rove theexistenceand uniqueness for the localsolution of them oving boundary p roblem(2.1).Ou rm ain resu lt is

        In order to p rove this theorem,for each h(t)∈Bt0,w e first consider follow ing p roblem

        Then from(3.18),(3.19)and Lemm a 3.2,w e know that for 0≤t1≤t2≤t0≤T0,

        here

        and c is independentof t0.Let M2denote the constan tat the righthand side of(4.4),if t0is sm allenough,then

        Thusw e can choose M0=M2,thatm eans s(t)∈Bt0.Observe that Bt0?C[0,t0]isa com pact, closed and convex subset.

        Define G:h(t)→s(t),then G m aps Bt0in to Bt0.We can p rove that G is a con tractive m app ing,then the fixed point theorem yields that there exist a pair(u,v)and a curve Γt:x=h(t)w hich are the solu tion of(4.1).

        In fact,for h1(t),h2(t)∈Bt0,let(u1,v1)and(u2,v2)rep resent the correspond ing solutionsof(4.2)respectively.Then for 0≤t≤t0,one has

        thatm eans them app ing G is contractive if 0<t0<1.Thusw e have p roved follow ing lemm a:

        Next,w e can deduce that

        Lemm a 4.2.Ifu0>0,k u0kL1(0,b)=1and(u,v)is the solution ofthe system(4.1),then for t0>0

        smallenough,wehaveu>0 and k u kL1(0,1)=k u0kL1(0,b)=1.

        Proof.Since u0(x)>0,by standard m axim alp rincip le of the parabolic equation,it follow s that u>0.Integrating the firstequation of(4.1)over(0,h(t)),w e have

        as required.

        ProofofTheorem 4.1. Considerω∈C([0,t0],L∞(0,1)),satisfying Rh(t)0ω(x,t)d x=1,andω= 0,for h(t)<x<1,0<t<t0.Let u∈Xσh(t0)be the correspond ing solu tion of(4.1),w e define am ap G1by G1(ω)=u.

        w here M=2C k u0kH2,and the constant C isgiven by theestim ate(3.4).Thus from Lemm a 4.1 and Lemm a 4.2,w e know that e BMis nonem p ty.

        By using Lemm a 3.1 and Lemm a 3.2,w e have

        Since the constan t C is independentof t0,so the estim ate above show s that

        for t0>0 sm allenough,w hichm eans that them app ing G1m apsin to

        Forω1,ω2∈e BM,let u1,u2denote the correspond ing solution of(4.1)respectively.Set

        Sim ilar to the p roof of Lemm a 3.1,one can obtain that for each 1<σ<2 and t0>0 sm all enough

        w here C dependson M bu t is independentof t0and h∈Bt0. On the other hand,w e have

        w hich im p lies that them app ing G1is contractive for t0>0 sm all enough.So it is p roved that,for a fixed h∈Bt0,the p roblem

        Concerning the uniquenessof the solu tion,from the p rocessabove,w e know that the solution u is unique,but the solu tion v is notunique since if(u,v)is a pair of solution of (2.1)then for any constan t c,(u,v+c)is also a pair of solu tion of(2.1).

        5 The exp licit rep resen tative of them oving boundary in a special case

        Letus consider a special case that k(x,t)=μ(t)∈C[0,T0].Then a d irect calcu lation gives follow ing unique solu tion:

        Thusw e have p roved follow ing resu lt:

        [1]Keller E.F.,Segel L.A.,Initiation of slim em old aggregation view ed asan instability.J.Theor. Biol.,26(1970),399-415.

        [2]Herrero M iguel A.,Vel′azquez Juan J.L.,Singu larity patterns in a chem otaxism odel.M ath. Ann.,306(1996),583-623.

        [4]Nanjund iah V.,Chem otaxis signal relaying and aggregation m orphology.J.Theor.Biol.,42 (1973),63-105.

        [5]Nagai T.,Blow-up of rad ially symm etric solu tions to a chem otaxis system.Adv.M ath.Sci. Appl.,5(1995),581-601.

        [6]Child ress S.,Chem otactic collapse in tw o d im ensions,Lectu re Notes in Biom ath.Sp ringer-Verlag,55(1984),61-66.

        [7]Chen H.,Wu S.,Them oving boundary p roblem in a chem otaxism odel.Comm.Pure Appl. Anal.,11(2012),735-746.

        10.4208/jpde.v27.n3.7 Sep tem ber 2014

        ?Correspond ing au thor.Emailaddresses:WUSH8@sina.com(S.Wu),yuebo060713@163.com(B.Yue)

        AM SSub jectClassifications: 35A 01,35K57,35M 10,35L10,47D03,35R35

        Chinese Lib rary Classifications: O175.28,O175.29

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