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        Comparison Principle of Very Weak Solutions for Nonhomogeneous Elliptic Equations

        2020-07-28 01:13:10XIESuying謝素英YANGChao楊超
        應(yīng)用數(shù)學(xué) 2020年3期
        關(guān)鍵詞:楊超

        XIE Suying(謝素英),YANG Chao(楊超)

        (College of Science,Hangzhou Dianzi University,Hangzhou 310018,China)

        Abstract: Under some suitable assumptions,a comparison principle of very weak solutions for quasi-linear elliptic equation?divA(x,?u) = f(x,u) is given by using McShane extension theorem to construct the Lipschitz continuous test function,and the corresponding results of some homogeneous equations are generalized.

        Key words: Very weak solution;Comparison principle;Lipschitz continuous test function;McShane extension theorem

        1.Introduction

        In this paper,we study a comparison principle of very weak solutions to nonhomogeneous elliptic equation

        In recent years,there exist many results of weak solutions for quasilinear elliptic equations.Gilbarg and Trudinger[1]established a comparison principle of classical solutions for secondorder quasilinear elliptic equation.Tolksdorf[2]generalized the results of [1] and obtained a comparison principle of weak solutions forDamascelli[3]studied a comparison principle of weak solutions(inW1,∞(?)) for?divA(x,?u)=g(x,u) by taking an appropriate test function.The right hand side of the equation(i.e.lower order term)in [1-3] satisfied non-increasing foru.The definition of very weak solutions for A-harmonic equation were given[4],Iwaniec et al.[5]obtained the existence and local integrability of very weak solutions to the A-harmonic equation by using Hodge decomposition method.By Hodge decomposition method to construct a proper test function,the uniqueness of the very weak solutions of?divA(x,?u)=f(x,u) is obtained under the condition of weak boundary value in [6].More references about Hodge decomposition see [7-9].

        Lewis[10]and ZHONG[11]studied the existence and uniqueness of very weak solutions forDmA(x,Dmu)=0 and?divA(x,?u) =μin Grand Sobolev space by using the method of maximal function to construct Lipschitz-type continuous test function.SHI[12]studied a comparison principle of very weak solutions to?divA(x,?u)=0 by the similar method in [10-11].ZHU[13]introduced a comparison principle of very weak solutions for?divA(x,u,?u) =f(x)+div(|?up?2|?u) by constructing a suitable test function,and combining Hardy-Littlewood maximum function et al.

        However,the comparison principle of very weak solutions to equation (1.1) has not been studied yet.Inspired by [6,11-12],we study a comparison principle of equation (1.1) by using McShane extension theorem to contract the Lipschitz continuous test function.Compared with the right hand side in [13],ourf(x,u) in (1.1) is more general,the reason is that the right hand side of [13] is actuallyf(x) which is independent ofu.In particular,owing to the appearance off(x,u) in the proof,we apply Theorem 2.7 in [14] (i.e.Lemma 2.3 in this paper),Sobolev embedding theorem,H?lder’s and Young’s inequalities in order to estimate the integral term off(x,u).In this paper,we assumef(x,u) to be non-increasing foru,so that our result also holds in classical solution and weak solution cases.

        2.Preliminary Lemmas and Main Result

        In order to prove the main result,we need the following lemmas.

        3.Proof of Theorem

        In the following proof,all the constantsCmay change from line to line.

        ProofLetu1,u2∈W1,r(?) are solutions of equation (1.1),andu1≥u2on??.We considerv(x)=min{0,u1?u2}and know thatv(x)∈W1,r0(?).From Lemma 2.1 and Lemma 2.2,there existsvλas Lipschitz continuous extension of functionv(x) onFλ ∪C?,andvλcan be used as a test function in Definition 1.1 because it satisfied (i)-(iv) from Lemma 2.2.Next we have

        Multiplying both sides of the above inequality byλ?1?ε(0<ε <1) and integratingλon(0,+∞),we deduce that

        By using H?lder’s and Young’s inequalities,we obtain

        whereε′′andC(ε′′) stand for the small and large constants respectively from Young’s inequality.

        Similar to [12],We distinguish the proof into two cases:

        Case 1p ≥2.In this case,by using H?lder’s inequality we have

        This is easy to implies

        Combining (3.5),(3.6),(3.7),(3.8)and (3.9),we have

        where the above inequality holds for all 0<ε ≤ε0<1,and C doesn’t depend onε.We letε →0,then we getu1=u2a.e.in?2and Theorem 2.1 were proved.

        Case 21

        that is,

        Combining (3.5),(3.6),(3.7) and (3.11),there have

        Similar to Case 1,we letε →0,and Theorem 2.1 is proved.

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