亚洲免费av电影一区二区三区,日韩爱爱视频,51精品视频一区二区三区,91视频爱爱,日韩欧美在线播放视频,中文字幕少妇AV,亚洲电影中文字幕,久久久久亚洲av成人网址,久久综合视频网站,国产在线不卡免费播放

        ?

        ON CONVERGENCE CONDITIONS OF LEAST-SQUARES PROJECTION METHOD FOR OPERATOR EQUATIONS OF THE SECOND KIND

        2017-04-12 14:31:39DUShukai
        數(shù)學雜志 2017年2期
        關鍵詞:收斂性武漢大學算子

        DU Shu-kai

        (School of Mathematics and Statistics,Wuhan University,Wuhan 430072,China)

        ON CONVERGENCE CONDITIONS OF LEAST-SQUARES PROJECTION METHOD FOR OPERATOR EQUATIONS OF THE SECOND KIND

        DU Shu-kai

        (School of Mathematics and Statistics,Wuhan University,Wuhan 430072,China)

        In this paper,we investigate the convergence conditions of least-squares projection method for compact operator equations of the second kind.By technics in functional analysis and Moore-Penrose inverse,we obtain 4 new mutually equivalent convergence conditions,which build the connections among several types of convergence conditions and provide us with more choices to examine the convergency of the approximation scheme.A simple and important example is also studied as an application of the theorem.

        convergence condition;least-squares projection;operator equation

        1 Introduction

        Operator equation was one ofthe principaltools in a large area ofapplied mathematics, and the literature discussing around this topic is vast.In this paper,we will limit our discussion on the compact operator equations of the second kind,which has the form

        where K:X → X is a compact operator and b ∈ X is given.Thanks to the First and the Second Riesz Theorem,we know dim N(T) < ∞ [6,Theorem 3.1,p.28],and R(T) was closed[6,Theorem 3.2,p.29].We aim to obtain the best-approximate solution of(1.1), which is denoted as x?:=T?b,where T?is the Moore-Penrose inverse of T.Note that as R(T)is closed,T?is naturally guaranteed to be bounded.

        Due to the complexity of the specific problems that has form(1.1),it is diffi cult for us to find a universal solution to all the problems.A more promising strategy is finding the numericalsolution,which involve approximating the abstract space and operator with finite freedoms.Let{Xn}be a sequence of finite-dimensionalsubspaces of X such thatand for each n ∈ N set Tn:=T Pn,where Pn:=PXnis the orthogonal projection from X onto Xn.Note that(1.2)implies

        here we say{(Xn,Tn)}n∈Nis a LSA(least-squares approximation setting)for T,and all of our following discussions will be based on this setting.Our target is to fi nd suitable LSA such that

        namely,x?:=T?b can be approximated by x?n:=T?nb.There were many works touching upon this problem such as Du[1,2],Groetsch[4],Groetsch-Neubauer[3],and Seidman[5]. Note that(1.4)does not naturally holds for equation(1.1),as Du’s example[2,Example 2.10] shows.To guarantee the convergency of the approximation scheme{T?n}for T?.Groetsch [4,Proposition 0]and Du[2,Theorem 2.8(d)]provide the following convergence conditions

        where(1.5)is the stability condition of LSA{(Xn,Tn)}n∈N,that is,

        However,as will show in a simple and important example,a direct examination of(1.5) could be diffi cult,but the examination of some other equivalent condition of(1.5)that we will soon give in our theorem can be very easy.

        In this paper,we willgive some equivalent characterizations for(1.4)(or(1.5)).These equivalent characterizations can not only increase our understanding on the convergence of this approximation scheme by offering different perspectives,but also provide us with some simple and ‘easy to check’criteria to examine the convergence.To proceed,we need the following notation

        Theorem 1.1For the compact operator equation(1.1)with LSA,the following propositions are equivalent:

        (c)There holds

        (e)There is a n?∈ N such that Xn?? N(T).

        In Section 2,we willgive some lemmas and the proofof Theorem 1.1.In Section 3,we willstudy some examples to further explain the theorem.

        2 Proofs

        To prove Theorem 1.1 we need to prepare several lemmas.

        Lemma 2.1Let T ∈ B(X)with dim N(T) < ∞,and have LSA{(Xn,Tn)}.

        (a)There hold

        (b)There is a n?∈ N such that

        (c)If R(T)is closed and

        then(1.5)holds.

        Proof(a)It is clear that

        and therefore

        N(T)∩ Xn? N(T)∩ Xn+1(?n), dim(N(T)∩ Xn) ≤ dim N(T) < ∞,

        and therefore there is a n?∈ N such that

        This implies that

        (c)Assume that sup?Tn??=+∞.Then by the uniform boundedness principle,there is an u ∈ X such thatn

        Hence there exists a subsequencesuch thaDue to(b),

        there is a n?∈ N such that

        Hence it follows from(2.1)that N(T) ∩ Xn=N(T) ? Xnfor n ≥ n?,and therefore

        kknknk

        This with T?∈ B(X)(by R(T)being closed)implies that

        that contradicts with ‖vk‖ =1.

        Lemma 2.2Let T ∈ B(X)have LSA{(Xn,Tn)}.Then

        ProofIt is clear that s-limG(Tn) ? w-l~im G(Tn).Hence,we need only to show that

        n→∞n→∞

        Let(x,y) ∈ G(T).Then(x,Tnx) ∈ G(Tn),and(x,Tnx) → (x,y)(n → ∞).Therefore (x,y) ∈ s-lim G(Tn).This gives that G(T) ? s-limG(Tn).Let(x,y) ∈ w-l~imG(Tn).

        n→∞∞n→∞n→∞

        Then there is a sequence{(xn,yn)}such that ∪k=nG(Tk) ? (xn,yn) ? (x,y)(n → ∞). Thus there is a sequence{kn}such that

        Note that for all v ∈ X there holds

        Thus we have 〈T x ? y,v〉=0 ?v ∈ X,that is,(x,y) ∈ G(T).This gives thatG(T).

        Lemma 2.3Let H be a Hilbert space and{Hn}a sequence of closed subspaces of H. Then

        in the case that{PHn}is strongly convergent,

        ProofSee[1,Lemma 2.13].

        Next,we prove Theorem 1.1 as follows.

        Proof of Theorem 1.1Note that,by Lemma 2.1(a),PN(Tn)=PN(T)∩Xn+I ? Pn, and there is a n?∈ N such that

        Therefore it follows that

        that is,

        Due to this with the uniform boundedness principle,it is clear that

        Let(a)be valid,namely,(1.4)and(1.5)hold(by(2.4)).Then for all x ∈ X there hold

        Thus we obtain that

        Let(y,x) ∈ G (T?).Then

        By Lemma 2.2,s-nl→im∞G(Tn)=G(T),hence there is a squence{xn}such that

        This with(2.6)implies that

        and therefore

        Hence,there is a sequence{kn}such that

        This with Tk?

        nyn∈ N(Tkn)⊥? Xknand(2.6)implies that

        and for any v ∈ X,

        Thus we have

        Hence to prove(c)we need only to show that

        Assume that(2.7)is not valid.Then there is a x0with ‖x0‖ =1. Note that,by(2.2)with Lemma 2.3,

        It follows that x0∈ N(T) ∩ (N(T) ∩ Xn?)⊥,and that x0satisfies

        and(noting N(Tn)⊥=(N(T)∩ Xn)⊥∩ Xn? Xn)

        So we have

        This contradicts with ‖x0‖ =1.

        (c)=? (d)Let(c)be valid.For any b,bn∈ X with ‖bn? b‖ → 0(n → ∞)we need only to show that

        Due to Lemma 2.3,(c)is equivalent toBy Lemma 2.1(a)and Lemma 2.3,the above equation is equivalent to(2.1).Then by Lemma 2.1(c),we obtain(1.5),that is

        Let x ∈ w-l~im T?1(Pb).Then there is a squence{x}with an integer sequence

        n→∞nR(Tn)nn{kn}such that

        Note that for all v ∈ X there holds

        and by use of(2.9),

        That gives x ∈ s-lim T?1(Pb).So we get

        n→∞nR(Tn)n

        Thus we get(d).

        (d)=? (e)Let(d)be valid.It is clear that

        By(2.2)and Lemma 2.3,there is a n?∈ N such that

        That gives(e).

        (e)=? (a)Let(e)hold.Then(2.1)is valid.Hence we have(1.5)by Lemma 2.1(c), that is(a)holds.

        3 Example

        In Theorem 1.1,one thing worth to notice is condition(e),which claims that the strong convergence of the LSA{(Xn,Tn)}n∈Nis equivalent to

        Note that the examination of this condition does not involve any computation of operator norm or generalized-inverse,which are unavoidable in the examination of the stability condition(condition(a)in Theorem 1.1).Here we willlook at a simple example to see how the condition(e)can be used in specific integralequation.

        Example 1Let X:=L2[?π,π],and we choose the approximation space as

        We consider the below integralequation of the second kind:

        where f ∈ L2[?π,π]is known,and we want to get ?.Let{Xn,Tn}be the LSA of the equation.It is easy to check that N(T)=span{x},and for x,it has the Fourier series As the non-zero coeffi cients in the series has infinite term,so it is obvious that there is no n?∈Nsuch that N(T) ? Xn?,namely,the convergence condition(e)in Theorem 1.1 doesrding to the Theorem 1.1,the stability condition fails in this case,and

        Here we look again on the stability condition(a),namely,

        We notice that to examine this condition,we need to compute generalized-inverse and operator norm,the cost ofwhich is almost equalto computing the minimalspectralof Tn.Thus, it is hard to find a unified method to achieve this task.

        Condition(e)in Theorem 1.1 also give the clue to choose convergent approximation scheme.For Example 1,to guarantee the convergence,we choose the approximation space as

        The above is the subspace spanned by the first(n+1)terms of the sequence of Legendre polynomial on[?π,π].Now the LSA{Xn,Tn}possesses convergency as a result of X2?N(T).

        [1]Du N.The basic principles for stable approximations to orthogonal generalized inverses of linear operators in Hilbert spaces[J].Numer.Funct.Anal.Optim.,2005,26(6):675–708.

        [2]Du N.Finite-dimensionalapproximation settings for infi nite-dimensional Moore–Penrose inverses[J]. SIAM J.Numer.Anal.,2008,46(3):1454–1482.

        [3]Groetsch C W,Neubauer A.Convergence of a general pro jection method for an operator equation of the fi rst kind[J].Houston J.Math.,1988,14(2):201–208.

        [4]Groetsch C W.On a regularization-Ritz method for Fredholm equations of the fi rst kind[J].J.Integ. Equ.,1982,4(2):173–182.

        [5]Seidman T I.Nonconvergence results for the application of least-squares estimation to ill-posed problems[J].J.Optim.The.Appl.,1980,30(4):535–547.

        [6]Kress R.Linear integral equations(2rd ed.)[M].New York:Springer-Verlag,1999.

        第二類算子方程最小二乘投影法的收斂性條件

        杜書楷
        (武漢大學數(shù)學與統(tǒng)計學院,湖北 武漢 430072)

        本文研究針對第二類緊算子方程的最小二乘投影法的收斂條件.通過泛函分析及廣義逆理論,得到了四個新的互相等價的收斂性條件,這些條件建立起了幾種不同收斂性之間的聯(lián)系并為人們檢驗逼近框架的收斂性提供了更多地選擇.文中也給出了對一些簡單且重要的例子的研究,以作為主要定理應用的范例.

        收斂條件;最小二乘投影法;第二類算子方程

        :47A52;65J20;15A09

        O241.2;O241.5

        tion:47A52;65J20;15A09

        A < class="emphasis_bold">Article ID:0255-7797(2017)02-0291-10

        0255-7797(2017)02-0291-10

        ?Received date:2014-12-19 Accepted date:2015-05-06

        Biography:Du Shukai(1990–),male,born at Wuhan,Hubei,master,major in Numerical Analysis.

        猜你喜歡
        收斂性武漢大學算子
        武漢大學
        校訓展示墻
        在武漢大學拜謁李達塑像
        擬微分算子在Hp(ω)上的有界性
        Lp-混合陣列的Lr收斂性
        各向異性次Laplace算子和擬p-次Laplace算子的Picone恒等式及其應用
        一類Markov模算子半群與相應的算子值Dirichlet型刻畫
        END隨機變量序列Sung型加權和的矩完全收斂性
        Roper-Suffridge延拓算子與Loewner鏈
        行為ND隨機變量陣列加權和的完全收斂性
        av国产免费在线播放| 欧美人妻日韩精品| 久久亚洲成a人片| 伊人久久大香线蕉av色婷婷| 人人妻人人澡人人爽欧美一区| 亚洲色成人网站www永久四虎| 国产手机在线αⅴ片无码| 国产av乳头久久一区| 粉嫩av最新在线高清观看| 无码国产福利av私拍| 亚洲AV无码精品蜜桃| 一区二区三区国产亚洲网站| 久草视频华人在线观看| 国语对白精品在线观看| 一本色道久久88亚洲精品综合| 在线永久看片免费的视频| 亚洲AV无码乱码一区二区三区 | 高清成人在线视频播放| 国内永久福利在线视频图片| 国产无遮挡裸体免费视频| 亚洲色偷偷综合亚洲AVYP| 青青草视频视频在线观看| 无码gogo大胆啪啪艺术| 最近高清中文在线字幕观看| 日韩少妇人妻一区二区| 国产精品久久久免费精品| 熟妇丰满多毛的大隂户| 亚洲欧美性另类春色| 亚洲综合中文日韩字幕| 精品偷拍被偷拍在线观看| 少妇三级欧美久久| 粗大挺进孕妇人妻在线| 无码 人妻 在线 视频| 日韩精品中文字幕无码一区| 国产爆乳美女娇喘呻吟久久| 色综合悠悠88久久久亚洲| 最新国产福利在线观看精品| 国产精品毛片无码久久| 国产农村妇女毛片精品久久麻豆| 亚洲av无码电影在线播放| 久久AⅤ无码精品为人妻系列|